Definite integral

Ram Lama

Student

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Evaluate the definite integral 02(322+1).

  • 26 Dec, 2023
Replies (1)
Harit Thakuri

Instructor

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Solution: To evaluate the definite integral, we first find the antiderivative of the given function and then apply the fundamental theorem of calculus.

(322+1)=32++

Now, evaluate the definite integral from 0 to 2:

[32+]02=(2322+2)(0302+0)

=(84+2)(0)=6

Therefore, 02(322+1)=6.


:)Happy Learning

  • 26 Dec, 2023

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